Because the signal decays with a finite decay time, the assumption that the root mean square voltage over one period is the peak voltage divided by is no longer valid. The corresponding value can be found by
where ω is the angular frequency, τ is the decay time and T is the time of one period in time t. Evaluating the integral gives
This is one case where the signal is given by a sine function. In the opposing case, where a cosine function is used instead, the expression evaluates to
Another effect is the signal decaying before the first peak in the oscillation is seen. The peak time in the case of a