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< <  Initially the fits file was loaded into python, the image was then projected onto the xaxis to obtain a spectrum. This was in the units of N_{adu} against position, so from the eqaution N_{pe} = 2.3*N_{adu} the data was plotted in N_{pe} against position.  
> >  Initially the fits file was loaded into python, the image was then projected onto the xaxis to obtain a spectrum. This was in the units of N_{adu} against position, so from the eqaution N_{pe} = 2.3*N_{adu} the data was plotted in N_{pe} against position.  
 
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> >  Comparison with Unfocused Image
For Comparison, an unfocused image taken from the Cadmium lamp was analysed. As before, the fits file was loaded into python, projected onto the x axis, and then multipled by the gain, 2.3, to gain the number of photoelectrons.
As you can see, the spectral lines have been broadened significantly, reducing the accuracy of locating the peaks. This shows the difference between the quality of the focused image and the unfocused image, highlighting the difference it would make to our data analysis. Questions to ask at next meetingon 14/10/15:
 
 
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l is equal to the expextation value and the variance, therefore for the distribution to be poisson the mean should be equal to the square of the standard deviation.  
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> >  Spectrum with removed background
The background could then be reomved from the inital spectra of the lamp leaving only the significant peaks. This was done by removing the mean+stdev.
 
 JosephBayley  13 Oct 2015
 
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< <  Initially the fits file was loaded into python, the image was then projected onto the xaxis to obtain a spectrum. This was plotted with N_{adu} against position, so from the eqaution N_{pe} = 2.3*N_{adu} the data was plotted against N_{pe}.  
> >  Spectrum
Initially the fits file was loaded into python, the image was then projected onto the xaxis to obtain a spectrum. This was in the units of N_{adu} against position, so from the eqaution N_{pe} = 2.3*N_{adu} the data was plotted in N_{pe} against position.
To calculate the background of the data, the position between 350 and 500 was selected, this have a plot of which had a bright pixel as shown,
mean = 149775.0, stdev = 20571.1, however for a poisson distribution where, f(n,l) = (l^n)( e^{l})/(n!) l is equal to the expextation value and the variance, therefore for the distribution to be poisson the mean should be equal to the square of the standard deviation.  
 JosephBayley  13 Oct 2015
 
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 JosephBayley  13 Oct 2015
